a man is 4 times as old as his son | More

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a man is 4 times as old as his son*******A man 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages. Open in App. Solution. Let the present age of the son = x years. .A man is four times as old as his son. The difference between their ages. Mathematics. WAEC 2001. A man is four times as old as his son. The difference between their ages .

A man 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages. View Solution. Q4. Ajay is 4 times as old as his son after 16 .

Man's present age : 40 years old. Let man's age = a Let son's age = b Since a man is 4 times as old as his son, therefore a = 4b In 5 years, he will only be 3 times . The man’s present age is 32 years, and his son’s present age is 8 years. We can observe that \[8 \times 4 = 32\]. Therefore, we have verified that the man’s .

At present time a man is four times as old as his son. Six years ago he was as 10 times as old. Find their present age.-----Equations: m = 4s m-6 = 10(s-6)----Substitute for "m" .A man is 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find the their present ages. Medium. View solution > Reena is twice as old as .A man is four times as old as his son. After 16 years he will be only twice old as his son. Find their present ages. Open in App. Solution. . Sanjeev is 4 times as old as his .

a man is 4 times as old as his sonlet m = the man's present age let s = son's age; a man nine times as old as his son. m = 9s: In nine years, he will be only three times as old as his son. m + 9 = 3(s + 3) m + 9 = 3s + 27 m = 3s + 27 - 9 m = 3s + 18 Replace m with 9s (from the 1st equation) 9s = 3s + 18 9s - 3s = 18 6s = 18 s = s = 3 yrs is son's age then m = 9(3) m = 27 yrs is .

A man is 4 times as old as his son. In 3 years, the father will be 3 times as old as his son. How old is each of them now? Here’s the best way to solve it. Let's establish the followings: a = the age of the son, now b = the age of the father, now. ..

Algebra -> Customizable Word Problem Solvers -> Age-> SOLUTION: a man is three times as old as his son. four years ago, he was four times as old as his son was at that time.how old is the son? i think its twelve. i've done it in a trial and Log On Ad: Over 600 . If the man's present age is 32, then 4 years ago, he was 28, which means his son was 4 years old 4 years ago (since we're told the man was seven times as old as his son at that time) If the son was 4 years old 4 years ago, and then the son is presently 8 years old, and the man's present age (32) is four time's the son's age. Answer: B

A man is four times as old as his son. The difference between their ages. Mathematics. WAEC 2001. A man is four times as old as his son. The difference between their ages is 36 years Find the sum of their ages. A. .Question 415703: a man is three times as old as his son. four years ago, the sum of their ages was 60 years. How old is the son Answer by ewatrrr(24785) (Show Source):MoreQ. Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times the ago of the son. Find the present ages of the man and his son.

a man is 4 times as old as his son MoreFive years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present age. View Solution. Q3. 5 years ago a man was 7 times as old as his son. After 5 years he will be thrice as old as his son. Find their present ages.

Let x = number of years until father will be 3 times as old as son. From the statement of the problem, we get our equation: 41+x = 3(9+x) 41 + x = 27 + 3x 41 = 27 + 2x 14 = 2x 7 = x. Therefore, in 7 years the man will be three times as old as the son.A man is 4 times as old as his son. After 16 years, he will be only twice as old as his son.Find their present ages. Open in App. Solution. Verified by Toppr. Let y be a man. . After 4 years he will be only 4 times as old as his son will be. What are their present ages.The son's age = x + 20 The father's age = 4x + 20 As in 20 years the father will be twice as old as his son, we can set up an equation: 4x + 20 = 2(x + 20) Solving the equation for x, we have 4x + 20 = 2x + 40 2x = 20 x = 10 So the age of his son now is 10, and the age of the the father now is 40.

(i) One year ago, a man was 8 times as old as his son. Now, his age is equal to the square of his son's age. Find their present ages. (ii) A man is 3 1 2 times as old as his son. If the sum of the squares of their ages is 1325, find the ages of the father and the son.

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a man is 4 times as old as his son|More